Sure, I'll take care of that. I also filed a bug for the H2 people.
Maybe they'll fix it, but at least we are back to building now.
mrg
On Sat, Oct 9, 2010 at 4:24 PM, Andrus Adamchik <andru..bjectstyle.org> wrote:
> Awesome. It worked.
>
> Can we possibly log a Jira about H2 auto increment feature and record it in RELEASE-NOTES? It should help us down the line in documenting 3.1 improvements.
>
> Andrus
>
>
> On Oct 9, 2010, at 7:05 PM, Michael Gentry wrote:
>
>> H2 1.1.119 ran tests successfully locally, so I've committed the POM
>> and hopefully Hudson will build cleanly now.
>>
>> mrg
>>
>>
>> On Sat, Oct 9, 2010 at 11:29 AM, Andrus Adamchik <andru..bjectstyle.org> wrote:
>>> I suggest filing a bug with H2 and downgrading down, until we (hopefully) find a version that is free of that bug but still supports auto-increment. If that doesn't work, we can switch tests to file-based URLs.
>>>
>>> Andrus
>>>
>>>
>>> On Oct 9, 2010, at 6:23 PM, Michael Gentry wrote:
>>>> Hi,
>>>>
>>>> I just did an experiment. Using H2 against a file (/tmp/CayenneTest)
>>>> it worked fine (returned one record). Against an in memory DB it
>>>> failed (returned 3 records). Seems like there is a bug in H2
>>>> somewhere. Thoughts on how we should handle this?
>>>>
>>>> Thanks,
>>>>
>>>> mrg
>>>>
>>>> PS. Here is the SQL:
>>>>
>>>>
>>>> CREATE TABLE ARTIST (ARTIST_ID BIGINT NOT NULL, ARTIST_NAME CHAR(254)
>>>> NOT NULL, DATE_OF_BIRTH DATE NULL, PRIMARY KEY (ARTIST_ID));
>>>> CREATE TABLE PAINTING (ARTIST_ID BIGINT NULL, ESTIMATED_PRICE
>>>> DECIMAL(10, 2) NULL, GALLERY_ID INTEGER NULL, PAINTING_DESCRIPTION
>>>> VARCHAR(255) NULL, PAINTING_ID INTEGER NOT NULL, PAINTING_TITLE
>>>> VARCHAR(255) NOT NULL, PRIMARY KEY (PAINTING_ID));
>>>>
>>>> INSERT INTO ARTIST (ARTIST_ID, ARTIST_NAME) VALUES (33001, 'B');
>>>> INSERT INTO ARTIST (ARTIST_ID, ARTIST_NAME) VALUES (33002, 'A');
>>>> INSERT INTO ARTIST (ARTIST_ID, ARTIST_NAME) VALUES (33003, 'D');
>>>> INSERT INTO PAINTING (PAINTING_ID, ARTIST_ID, PAINTING_TITLE,
>>>> ESTIMATED_PRICE) VALUES (33009, 33001, 'X', 5000);
>>>> INSERT INTO PAINTING (PAINTING_ID, ARTIST_ID, PAINTING_TITLE,
>>>> ESTIMATED_PRICE) VALUES (33010, 33001, 'Y', 5000);
>>>> INSERT INTO PAINTING (PAINTING_ID, ARTIST_ID, PAINTING_TITLE,
>>>> ESTIMATED_PRICE) VALUES (33011, 33002, 'Z', 5000);
>>>>
>>>> SELECT t0.DATE_OF_BIRTH AS ec0_0, t0.ARTIST_ID AS ec0_2,
>>>> t0.ARTIST_NAME AS ec0_1 FROM ARTIST t0 LEFT OUTER JOIN PAINTING t1 ON
>>>> (t0.ARTIST_ID = t1.ARTIST_ID) WHERE t1.PAINTING_ID IS NULL;
>>>>
>>>
>>>
>>
>
>
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