Awesome. It worked.
Can we possibly log a Jira about H2 auto increment feature and record it in RELEASE-NOTES? It should help us down the line in documenting 3.1 improvements.
Andrus
On Oct 9, 2010, at 7:05 PM, Michael Gentry wrote:
> H2 1.1.119 ran tests successfully locally, so I've committed the POM
> and hopefully Hudson will build cleanly now.
>
> mrg
>
>
> On Sat, Oct 9, 2010 at 11:29 AM, Andrus Adamchik <andru..bjectstyle.org> wrote:
>> I suggest filing a bug with H2 and downgrading down, until we (hopefully) find a version that is free of that bug but still supports auto-increment. If that doesn't work, we can switch tests to file-based URLs.
>>
>> Andrus
>>
>>
>> On Oct 9, 2010, at 6:23 PM, Michael Gentry wrote:
>>> Hi,
>>>
>>> I just did an experiment. Using H2 against a file (/tmp/CayenneTest)
>>> it worked fine (returned one record). Against an in memory DB it
>>> failed (returned 3 records). Seems like there is a bug in H2
>>> somewhere. Thoughts on how we should handle this?
>>>
>>> Thanks,
>>>
>>> mrg
>>>
>>> PS. Here is the SQL:
>>>
>>>
>>> CREATE TABLE ARTIST (ARTIST_ID BIGINT NOT NULL, ARTIST_NAME CHAR(254)
>>> NOT NULL, DATE_OF_BIRTH DATE NULL, PRIMARY KEY (ARTIST_ID));
>>> CREATE TABLE PAINTING (ARTIST_ID BIGINT NULL, ESTIMATED_PRICE
>>> DECIMAL(10, 2) NULL, GALLERY_ID INTEGER NULL, PAINTING_DESCRIPTION
>>> VARCHAR(255) NULL, PAINTING_ID INTEGER NOT NULL, PAINTING_TITLE
>>> VARCHAR(255) NOT NULL, PRIMARY KEY (PAINTING_ID));
>>>
>>> INSERT INTO ARTIST (ARTIST_ID, ARTIST_NAME) VALUES (33001, 'B');
>>> INSERT INTO ARTIST (ARTIST_ID, ARTIST_NAME) VALUES (33002, 'A');
>>> INSERT INTO ARTIST (ARTIST_ID, ARTIST_NAME) VALUES (33003, 'D');
>>> INSERT INTO PAINTING (PAINTING_ID, ARTIST_ID, PAINTING_TITLE,
>>> ESTIMATED_PRICE) VALUES (33009, 33001, 'X', 5000);
>>> INSERT INTO PAINTING (PAINTING_ID, ARTIST_ID, PAINTING_TITLE,
>>> ESTIMATED_PRICE) VALUES (33010, 33001, 'Y', 5000);
>>> INSERT INTO PAINTING (PAINTING_ID, ARTIST_ID, PAINTING_TITLE,
>>> ESTIMATED_PRICE) VALUES (33011, 33002, 'Z', 5000);
>>>
>>> SELECT t0.DATE_OF_BIRTH AS ec0_0, t0.ARTIST_ID AS ec0_2,
>>> t0.ARTIST_NAME AS ec0_1 FROM ARTIST t0 LEFT OUTER JOIN PAINTING t1 ON
>>> (t0.ARTIST_ID = t1.ARTIST_ID) WHERE t1.PAINTING_ID IS NULL;
>>>
>>
>>
>
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