"likeIgnoreCase" is not valid in EJBQL. Although the error message
refers to something else... strange...
On Dec 4, 2009, at 4:12 AM, Dave Lamy wrote:
> Hey guys--
>
> I'm really just now getting into using the EJBQLQuery and am having
> some
> difficulties. I don't know whether I'm doing something
> fundamentally wrong
> or what.
>
> Here's my EJBQL expression that I'm trying to get parsed (running
> 3.0B1):
>
> select COUNT(foo) from ProductCollection foo where
> foo.productStyles.taxonomy likeIgnoreCase '323.%'
>
> Parsing this query yields the following exception:
>
>
> org.apache.cayenne.ejbql.parser.ParseException: Encountered "
> <IDENTIFIER>
> "foo "" at line 1, column 53.
> Was expecting:
> "(" ...
>
> at
> org
> .apache.cayenne.ejbql.parser.EJBQL.generateParseException(EJBQL.java:
> 9419)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.jj_consume_token(EJBQL.java:
> 9298)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.conditional_primary(EJBQL.java:
> 1933)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.conditional_factor(EJBQL.java:
> 1911)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.conditional_term(EJBQL.java:
> 1776)
> at
> org
> .apache.cayenne.ejbql.parser.EJBQL.conditional_expression(EJBQL.java:
> 1738)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.conditional_primary(EJBQL.java:
> 1928)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.conditional_factor(EJBQL.java:
> 1911)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.conditional_term(EJBQL.java:
> 1776)
> at
> org
> .apache.cayenne.ejbql.parser.EJBQL.conditional_expression(EJBQL.java:
> 1738)
> at org.apache.cayenne.ejbql.parser.EJBQL.where_clause(EJBQL.java:
> 1585)
> at
> org.apache.cayenne.ejbql.parser.EJBQL.select_statement(EJBQL.java:69)
> at org.apache.cayenne.ejbql.parser.EJBQL.parseQuery(EJBQL.java:41)
> ...
>
> The statement looks legit to me. Is there like a fundamental
> something I'm
> not understanding about EJBQL? I saw some docs that showed doing
> this sort
> of join alias "IN" thing,
>
> SELECT OBJECT(e) FROM Department d, IN(d.employees) e
> WHERE d.name = ?1 AND e.salary > ?2
>
> My problem is that I'm using Expression.toEJBQL() to gen the where
> clause..
> was hoping to not have to recreate my code that generates the
> Expression
> object.
>
> Help!
>
> Dave
This archive was generated by hypermail 2.0.0 : Fri Dec 04 2009 - 08:32:14 EST