Hi everyone,
I'm taking my first steps with EJBQL.
Can someone spot the error in the following statement?
SELECT count(t) FROM User t WHERE
(upper(t.email) LIKE upper('%andreas.hartman..mail.com%')) OR
(upper(t.email) LIKE upper('%nobb..acbay.de%'))
The exception is:
Caused by: org.apache.cayenne.ejbql.parser.ParseException: Encountered "
"UPPER" "upper "" at line 1, column 36.
Was expecting one of:
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
"(" ...
at
org.apache.cayenne.ejbql.parser.EJBQL.generateParseException(EJBQL.java:9419)
at
org.apache.cayenne.ejbql.parser.EJBQL.jj_consume_token(EJBQL.java:9298)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_primary(EJBQL.java:1933)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_factor(EJBQL.java:1911)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_term(EJBQL.java:1776)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_expression(EJBQL.java:1738)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_primary(EJBQL.java:1928)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_factor(EJBQL.java:1911)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_term(EJBQL.java:1776)
at
org.apache.cayenne.ejbql.parser.EJBQL.conditional_expression(EJBQL.java:1738)
at
org.apache.cayenne.ejbql.parser.EJBQL.where_clause(EJBQL.java:1585)
at
org.apache.cayenne.ejbql.parser.EJBQL.select_statement(EJBQL.java:69)
Thanks a lot in advance!
Best regards,
Andreas
-- Andreas Hartmann, CTO BeCompany GmbH http://www.becompany.ch Tel.: +41 (0) 43 818 57 01
This archive was generated by hypermail 2.0.0 : Wed Jan 20 2010 - 12:29:55 EST